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PHYS 122 Midterm: EquationSheetExam2

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turquoisegnu128
31 Jan 2019
School
UW
Department
Physics
Course
PHYS 122
Professor
All

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Document Summary

E = 1. 60 10 19 c k = 8. 99 10 9 n m 2 / c2. = 8. 85 10 12 c2 /(n m 2 ) m e. Electric flux for uniform field = ea cos . Electric field due to a line of charge of infinite length. Electric field on the axis of a charged ring. Electric field due to point charge. Electric field due to a system of points. Potential energy of a dipole. Electric field for continuous charge distribution t = 1. + a t x av x = 1 v. U = pe cos + u 0. Electric field on the axis of a charged disk. Electric field due to an infinite plane. Electric field due to a thin spherical shell. Electric field due to a uniformly charged solid sphere. Potential due to a system of point charges. V = kq (v = 0 if r = ) r. (v = 0 if ri kqi ri i.

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Physics: Principles with Applications
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ISBN: 9780321625922

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Related Questions

1- A 40.0cm diameter loop is turned to the position where the largest flux is handled in a uniform electric field. In this position, the flux is obtained as 5.20 × 10 ^ 5 N.m ^ 2/c Find the twist of the electric field.

2- An electron was released from rest in a uniform electric field of 5.90 × 10 ^ 3 V / m. How much potential awareness (V) will pass after 1cm movement, and what is the time of the electron in position (m / s)? [m (e) = 9.11 × 10 ^ -31 kg, | q (e) | = 1.60 × 10 ^ -9 C.]

A cyclotron accelerates two protons directly toward each other,each with a speed of 1050 km/s, measured relative to the earth.Find the maximum electric force that these protons will exert oneach other.


This is all the information I was given, and this is how I tried tosolve. Can someone please work the problem? I'm out of time, andcompletely frazzled. All of my calculations have been wrong.

V = 1050 km/s
Permittivity of free space (e0) = 8.85*10-12
Mproton= 1.67*10-27
Charge of electron (e) = 1.602*10-19
1. k = 1/4*pi*e0 = 1.3 * 1011
2. r = ke2/mv2 = 5.84 * 1021
3. Fmax = ke2/r2 =?
e0

A coil of wire is connected to a power supply, and a currentruns in the coil. A single loop of wire is located near the coil,with its axis on the same line as the axis of the coil. The radiusof the loop is 2 cm.




At time t1 the magnetic field at the center of the loop, due to thecoil, is 0.4 T, in the direction shown in the diagram; the currentin the coil is constant.

(a) What is the absolute value of the magnetic flux through theloop at time t1?
Φ mag = T m2
(b) What approximations or assumptions did you make in calculatingyour answer to part (a)?

Check all that apply.

1.The magnitude of the magnetic field due to the coil is uniformover the area of the loop.
2.The magnetic field outside the loop is zero.
3. The magnetic field due to the coil is uniform in direction overthe area of the loop.


(c) What is the direction of the "curly" electric field inside thewire of the loop at time t1? (Remember that at this time thecurrent in the coil is constant.)
E = 0

At a later time t2, the current in the coil begins todecrease.

(d) Now what is the direction of the "curly" electric field in theloop?
counter-clockwise
At time t2 the rate of change of the magnetic field at the centerof the loop, due to the coil, is -0.36 T/s.
(e) At this time, what is the absolute value of the rate of changeof the magnetic flux through the loop?
|dΦmag/dt| = T m2/s
(f) At this time, what is the absolute value of the emf in theloop?
|emf| = V
(g) What is the magnitude of the electric field at location P,which is inside the wire?
|E| = V/m
(h) Now the wire loop is removed. Everything else remains as it wasat time t2; the magnetic field is still changing at the same rate.What is the magnitude of the electric field at location P?
|E| = V/m