STATISTC 515 Final: STAT 515 UMass Amherst STAT515Summer2016Final

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31 Jan 2019
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Stat 515 fall 2015 mid2 solutions: (a) note that b > 0 and hence f (y) 0. = 0 ( 1) = 1. dy = b y2 f (y)dy =z b. F (y) = p (y y) =z y f (z)dz = b. = 1 b y , y b, b z(cid:12)(cid:12) z2 dz = b. P (y > b + c) = 1 p (y b + c) = 1 f (b + c) = 1 (1 elsewhere. b. P (y > b + d | y > b + c) = P (y > b + c) b b+d b b+c. + d: (a) let y be the sat score, and y n (480, 1002). P (y 550) =z 550 z 18. = z = 22. 2 (b) let z be the cut-o score, then (c) P ( 2 < y < + 2 ) 1 .

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