36225 Chapter Notes - Chapter 14: Chi-Squared Test, Contingency Table, Confidence Interval
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14. 1: h0: p1 = . 41, p2 = . 10, p3 = . 04, p4 = . 45 vs. ha: not h0. 89 observed expected 200(. 41) = 82 200(. 10) = 20 200(. 04) = 8 200(. 45) = 90. Since evidence to conclude the proportions differ: using the applet, p value = p( 2 > 3. 696) = . 29622. 05. = 7. 81473, we fail to reject h0; there is not enough. 2: h0: p1 = . 60, p2 = . 05, p3 = . 35 vs. ha: not h0. 05. = 7. 37776, we can reject h0 and conclude that the current degrees of freedom. 2 admission rates differ from the previous records: using the applet, p value = p( 2 > 28. 386) = . 00010. 14. 3 the null hypothesis is h0: p1 = p2 = p3 = p4 = 4. 4 observed 294 276 238 192 expected 250 250 250 250. 05. = 7. 81473, we reject h0 and conclude that the lanes are.
