All Educational Materials for Jason Kronewetter

Is harder to recognize when to undo the chain rule when finding the integral. Take the derivative of (cid:1858)((cid:1876)) = (cid:1871)((cid:1876)(cid

Math 2b: sample final 3: turn off your cell phone and do not check it during the exam, no calculators or other forms of assistance allowed, this exam c

Cross out incorrect scratch-work: no calculators or other forms of assistance are allowed. 1 x x2 4 dx: (15 points) determine whether the following imp

Problems #1 and 4 are worth 15 points each, problem. #2 is worth 10 points and problems #3 and 5 are worth 25 points each. Please show all work needed

Cross out incorrect scratch-work: no calculators or other forms of assistance are allowed. 4 ]: a particle moves along a line so that its velocity at t

Cross out incorrect scratch-work: no calculators or other forms of assistance are allowed. 5 f (x) 3 4 6 9 13 18. 0 f (x) dx: estimate r 4. 1 f (x) dx

Cross out incorrect scratch-work: no calculators or other forms of assistance are allowed. 1 x x2 4 dx: (15 points) determine whether the following imp

This exam contains 10 pages (including this cover page) and 5 problems. Check to see if any pages are missing. Enter all requested information on the t

Math 2b - lecture 5 - indefinite integral and net change theorem. From fundamental theorem of calculus, we know that: Part i: g"(t) = (x) dx f(t) f t d

Math 2b - lecture 2 - areas and distances. The starting point of integral calculus is the problem of calculating area . The na ve concept of area comes

The line integral (cid:2194) around this curve is 3. 83 10-4 t m. The figure at right shows, in cross-section, three conductors that carry currents thr

5. 4 - indefinite integrals and the net change theorem. , then the most general antiderivative of f. Find the most general antiderivative of : a) in (x

Is harder to recognize when to undo the chain rule when finding the integral. Take the derivative of (cid:1858)((cid:1876)) = (cid:1871)((cid:1876)(cid