BIOC2000 Lecture Notes - Lecture 28: Oxyanion Hole, Conjugate Acid, Deprotonation

47 views2 pages
21 Jun 2018
School
Department
Course
Monday, 14 May, 2018
Gilam Lec
How different AA contribute to catalysis (role)
-Acid base mechanism of electron pushing (DHAP Intermediate not very stable
breaksdown to DA3P residue taking proton
-conjugate acid donating proton
-Electrostatic catalysis
-promote movement of electrons (lys positive)
-improve efficiency of reaction
-help orient
-deprotonation of substrates
-stabilise TS
-interact with side chains and change their property by pka
-covalent bond alternative pathway for product
-2 intermediates, some residues leave after 1 intermediate reach
-oxyanion hole form bond
-cleave bond with water hydrolysis serine pick up p from his to cleave bond
-serine and histadin reform
-aromatic group binds to hydrophobic pocket
-ser no h gp
-existing as conjugate base form is better change p off better nucleophile in water
-form covalent bonding to keep hold s and intermediate without dissociate and interact
with water
-Quantify enzymen and see how efficient they are
-enzymes produce product in high yield
-how
-rate increase with s conc
-enzymes are saturable
-time is kinetic
1
Unlock document

This preview shows half of the first page of the document.
Unlock all 2 pages and 3 million more documents.

Already have an account? Log in

Document Summary

Acid base mechanism of electron pushing (dhap intermediate not very stable breaksdown to da3p residue taking proton. Interact with side chains and change their property by pka. 2 intermediates, some residues leave after 1 intermediate reach. Cleave bond with water hydrolysis serine pick up p from his to cleave bond. Existing as conjugate base form is better change p off better nucleophile in water. Form covalent bonding to keep hold s and intermediate without dissociate and interact with water. Quantify enzymen and see how ef cient they are. If time change to s conc, rectangular hyperbola. Enzymes working as hard as they can already with substrate,saturation. Rate decrease with x s conc s depleted p build up. When measure initial rate where rate is maximal, we can neglect k2. Vo is initial rate p conc/time = k2 x [es] Es con constant while s doen p up. Break of es / build up of es.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related Documents