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CHEM 1F92 Lecture Notes - Lecture 11: Titration Curve, Sodium Hydroxide, Equivalence Point

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OC767021
4 Feb 2016
School
Brock University
Department
Chemistry
Course
CHEM 1F92
Professor
Theocharis C Stamatatos
CHEM1F90
Jan.27th,2016
ACIDSANDBASES(Continued)
Reviewfromlastclass
Strongacid/strongbasetitration
H+ + OH→ H2O
pHisdeterminedbytheconcentrationofexcessunreactedH+orOH
pH=7atequivalencepoint(completeneutralization)forstrongacidstrongbasetitrationonly!
pH<7strongacid/weakbasetitration
pH>7strongbase/weakacidtitration
Choosinganindicator:colourtransitionrangeshouldmatchpHattheequivalencepoint(mole
H+=moleOH)
Preferablythecolourchangeshouldoccurentirelywithinthesteepportionofthetitrationcurve
Ex.Weakacidstrongbasetitration:0.100MCH3COOHwith0.100MNaOH
*WhatisthepHattheequivalencepointforHFtotitratewith0.100MNaOH?
Answer:pH>7
HFistheonlyweakacidofthehalidegroup
Titrationisbetweenaweakacidandastrongbase
pHwillbe>7becausebasewillpredominate
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