ELEC 3909 Lecture Notes - Lecture 2: Horse Length
23 Feb 2016
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Problem 2. 14 for a distortionless line [see problem 2. 13] with z0 = 50 , = 20 (mnp/m), up = 2. 5 108 (m/s), nd the line parameters and at 100 mhz. Solution: the product of the expressions for and z0 given in problem 2. 6 gives. 50 = 1 ( /m), and taking the ratio of the expression for z0 to that for up = / = 1/ l c gives. 2. 5 108 = 2 10 7 (h/m) = 200 (nh/m). With l known, we use the expression for z0 to nd c : 2 10 7 (50)2 = 8 10 11 (f/m) = 80 (pf/m). The distortionless condition given in problem 2. 6 is then used to nd g . = 4 10 4 (s/m) = 400 ( s/m), and the wavelength is obtained by applying the relation.
