ENGR 213 Lecture 10: 3.5_Variation_of_Parameters

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Differentiate yp y =p u y +1 1 y =p y u +1. 1 y =p u y +1 1 y u +1 1 u y +1 1 y u +1 1 u y +1. 1 u y2 2 u y +2 2 u y +2 2 y u2 2 y u +2. Substituting the derivatives in this equation y +p. With two desired equations, we can find the solution of the system by. Cramer"s rule y u +1 1 y u +1 1 y u =2 2 y u =2 2. 3. 5 variation of parameters1method of variation of parametersintegral-defined functionshigher-order equations y " . 4m + 4 = (m " 2) =2. W =2 u =1 u =2 y =p ( " x "3 e4x (x+1)e4x. "x "2 x + 1 " u =2 x " u =1 " x "3. 2 x e y + y +c y =p. 1 = 0 " m =1 "1, m =2.

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