ENGR 243 Lecture Notes - Lecture 1: Escape Velocity

• School: Concordia University
• Department: Engineering
• Course: ENGR 243
• Professor: ALL

Document Summary

Equation for determining velocity x=2t3 - 9t2 + 12t + 10 v= dx/dt a= dv/dt, a= d2x/dt2. According to the equation, the velocity will be: v= 6t2 - 18t + 12 v = 6 (t2 - 3t +2) = 6 (t-2) (t-1) No need to consider time, in this equation you don"t have time. vdv = -gr2 / r2 dr. { o ve vdv = { a r - gr2/r2 dr = a - ve2 = gr2/r } v r = -ve2 / 2 = +gr ve = 2gr. 11. 51) vb = 300 mm/s: va , vc, vd, v c/a = relative velocity of toa xo+ (xo - xa) +2 (l - xa) = c. Xb + (xo - xa) -2xa = c - 2l. Xb + (xb - xa) - 2xa = constant d / dt (x6t (xb - xa) - 2xa) = d/dt (c) B + b - a - 2 a = 0.