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Lecture 6

Lecture 6 - 2.1 & AppD.pdf

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Department
Mathematics & Statistics (Sci)
Course
MATH 140
Professor
Ewa Duma
Semester
Summer

Description
THE TANGENT AND VELOCITY PROBLEMS 2.1 In this section we see how limits arise when we attempt to find the tangent to a curve or the velocity of an object. MATH140 - Lecture 6 Notes THE TANGENT PROBLEM Tangent Problem: The word tangent is derived from the Latin word tangens, which means “touching.” Thus t A tangent to a curve is a line that touches the curve. A tangent line should have thee should have the same direction as the curve at the point of contact. How can this idea be made same direction as the curve at the point of contact. precise? For a circle we could simply follow Euclid and say that a tangent is a line that intersects Ithe circle once and only once as in Figure 1(a). For more complicated curves this defini- tangent. Typically, this is not enough information to solve the problem because you needcurve (a) C. The line l intersects C only once, but it certainly does not look like what we think of as two points to find the slope and y-intercept. a tangent. The line t, on the other hand, looks like a tangent but it intersects C twice. P To be specific, let’s look at the problem of trying to find a tangent line t to the parabola t C Fy ▯ x in the following example.e equation of the tangent line, you need to get solve for the equation y = mx+b where m is the slope and b is the y-intercept. 2 l V EXAMPLE 1 Find an equation of the tangent line to the parabola y ▯ x at the Tpoint P▯1, 1▯.e, you can use the following equation: m = (y2-y1)/(x2-x1) (b) SOLUTION We will be able to find an equation of the tangent line t as soon as we know its Tslope m. The difficulty is that we know only one point, P, on t, whereas we need two FIGURE 1 points to compute the slope. But observe that we can compute an approximation to m by Example: Find an equation of the tangent line to the parabola y = x^2 at the point P(1,1) y *NOTE* Prof used example from textbook. Q{x,▯▯} t We choose x ▯ 1 so that Q ▯ P. Then 2 y=▯ P(1,▯1) m ▯ x ▯ 1 PQ x ▯ 1 0 x For instance, for the point Q▯1.5, 2.25▯ we have FIGURE 2 2.25 ▯ 1 1.25 m PQ▯ 1.5 ▯ 1 ▯ 0.5 ▯ 2.5 x mPQ The tables in the margin show the values of PQfor several values of x close to 1. The closer Q is to P, the closer x is to 1 and, it appears from the tables, the clis to 2. 2 3 PQ 1.5 2.5 This suggests that the slope of the tangent line t should be m ▯ 2. 1.1 2.1 We say that the slope of the tangent line is the limit of the slopes of the secant lines, 1.01 2.01 and we express this symbolically by writing 1.001 2.001 2 lim m PQ▯ m and lim x ▯ 1 ▯ 2 x mPQ Q lP xl1 x ▯ 1 0 1 Assuming that the slope of the tangent line is indeed 2, we use the point-slope form 0.5 1.5 0.9 1.9 of the equation of a line (see Appendix B) to write the equation of the tangent line 0.99 1.99 through ▯1, 1▯ as 0.999 1.999 y ▯ 1 ▯ 2▯x ▯ 1▯ or y ▯ 2x ▯ 1 Velocity Problems: 83 Similar to tangent problems, using the same equation, but to find the instantaneous velocity. EXAMPLE 1 A24 ||||APPENDIX D TRIGONOMETRY (a) Find the radian measure of 60.▯ (b) Express 5▯▯rad in degrees. SOLUTION (a) From Equation 1 or 2 we see that to convert from degrees to radians we multiply by D TRIGONOMETRY ▯ ▯180. Therefore ANGLES 60▯ ▯ 60 ▯ ▯ ▯ rad Trigonometry Review: ▯180 3 Angles can be measured in degrees or in radians (abbreviated as rad). The angle given by a complete revolutioAngles can be measured in degrees or in radian
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