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Lecture

# November 20.doc

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School
McGill University
Department
Physics
Course
PHYS 101
Professor
Kenneth Ragan
Semester
Fall

Description
Phys 101 Alanna Houston November 20, 2007 - Primarily see virtual image - In the example of a real image, you would only see the image clearly if you were further from the mirror than the image (so your eye received diverging rays) - Concave shapes can also be used for other waves (sound mirror) - Convex mirrors can also use the mirror equation. Focal length is: f = r/2 - Careful with the sings of distances: f is negative in this case (but the rest of our sign convention is unchanged) - A convex right-hand rear view mirror on a car. Radius of curvature is 16.0 m. What is the image location and magnification for an object 10.0 m away? Most mirrors like this carry a warning: “objects in this mirror may be closer than they appear!” Why? o r = 16.0 m o f = -8.0 m o 1/do + 1/di = 1/f o 1/di = -1/8 – 1/10 o -4.44 m = di o m = -4.4 / 10 = +0.44 - You look into a shiny Christmas tree ball (diameter 9.0 cm) from 30.0 cm away. Where is your image? Is it real or virtual? Upright of inverted? o 1/do + 1/di = 1/f o r = 4.5 cm o f = -2.25 cm o –1/2.25 = 1/30 + 1/di o di = -2.09 cm = 2.1 cm o m = -di / do = - -2.1/3.0 = 1/15 = upright o therefore, virtual and upright THIN LENSES - made up of spherical surfaces where the radius of curvature is large compared to the lens size so we ignore spherical aberration: that is, we assume that parallel rays are focussed at the focal point at the focal length f from the lens: look at picture - look at pictures of converging and diverging lenses. - With ray tracing, we can draw the position of the image
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