BIOLOGY 1A03 Lecture Notes - Gene Expression, Model Organism, Prokaryote

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BIOLOGY 1A03 Full Course Notes

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Biology chapter 17: control of gene expression in bacteria. Gene expression occurs when a gene product is actively being synthesized and used in a cell. Regulation of gene expression is critical to the efficient use of resources and so to survival. Transcription and translation of genes in bacteria were predicted to be triggered by specific signals from the environment. Gene expression can be controlled at any step between the synthesis of rna and the activation of the final gene product. How can a bacterial cell avoid producing proteins that are not needed at a particular time and thus use resources efficiently: the cell could avoid making the mrnas for particular enzymes. If there is no mrna, then ribosomes cannot make the gene product. Various regulatory proteins affect the ability of rna polymerase to bind to a promoter and initiate transcription. Genes that are controlled in this way are said to undergo transcriptional control.

Related Questions

HELP ASAP;

Please help me understand my lab results, so be detailed to clearly understand . INclude answers to these questions what role does ampicilin (amp) and arabinose (ara) play in the experiment. Because GFP was isolated from jelly fisht, what modification to the GFP DNA had to be made to result in expression in E. coli?

BACKGROUND INFORMATION

Transformation of GFP and the pGLO Plasmid

GFP is a commonly used reporter protein in research labs, as the fluorescence creates a marker protein that can be used in many types of cell biology and biochemical studies. In basic research, GFP is often fused to a specific target protein of interest, creating a chimeric reporter protein. GFP has been used as a reporter protein to study blood vessel and tumor progression in mice, brain activity in mice, and malaria eradication in mosquitoes for instance (see website mentioned in notes).

In the first week you will use a procedure to genetically transform bacteria with the gene that codes for Green Fluorescent Protein. Following the transformation procedure, the bacteria express their newly acquired jellyfish gene and produce the fluorescent protein, which causes them to glow a brilliant green color under ultraviolet light. During the second week you will purify the protein away from all of the other proteins produced by the bacteria using chromatography, and during the third week you will evaluate the success of the purification procedure and estimate the size (molecular weight) of GFP by using sodium dodecylsulfate polyacrylamide gel electrophoresis (SDS-PAGE).

Fundamental to the process of genetic transformation of bacteria are plasmids. In addition to one large chromosome, bacteria naturally contain one or more small circular pieces of DNA called plasmids. Plasmid DNA usually contains genes for one or more traits that may be beneficial to bacterial survival. In nature, bacteria can transfer plasmids back and forth allowing them to share these beneficial genes. This natural mechanism allows bacteria to adapt to new environments. The occurrence of bacterial resistance to antibiotics is due in large part to the transmission of plasmids which contain antibiotic resistance genes.

The pGLO plasmid (Fig. 5, not a naturally occurring plasmid) contains the gene for GFP, and also contains the gene for the enzyme Î²-lactamase (bla), which provides resistance to the antibiotic ampicillin. The Î²-lactamase protein is produced and secreted by bacteria that contain the plasmid. Î²-Lactamase inactivates the ampicillin present in the LB nutrient agar, allowing bacterial growth. Only transformed bacteria that contain the plasmid and express Î²-lactamase can survive on plates that contain ampicillin. Only a very small percentage of the cells take up the plasmid DNA and are transformed. Untransformed cells cannot grow on the ampicillin selection plates. pGLO also incorporates a special gene regulation system, which can be used to control expression of the fluorescent protein in transformed cells. The gene for GFP can be switched on in transformed cells by adding the sugar arabinose to the cellsâ nutrient medium. Selection for cells that have been transformed with pGLO DNA is accomplished by growth on antibiotic plates. Transformed cells will appear white (wild-type phenotype) on plates not containing arabinose, and fluorescent green when arabinose is included in the nutrient agar medium.

for the first week section of lab

To each of two microfuge tubes, add 250ul of transformation buffer. Keep these tubes on ice.

Using a sterile loop, pick one colony of bacteria from the LB plate.

Transfer this colony to one of the microfuge tubes. Gently vortex the tube until the colony is dispersed. Repeat for the second tube.

Add 0.08ug of DNA to one of these tubes (+DNA tube).

Incubate both tubes on ice for 10 minutes.

Incubate both tubes at 42Â°C for 50 seconds.

Incubate both tubes on ice for 2 minutes.

Add 250ul of LB broth to each tube and incubate at room temperature for 10 minutes.

Flick each tube gently. Add 100ul of this transformation mix to the appropriate plates.

Results:

+DNA: LB/amp--> 1 colony, Glow: uncertain

+DNA: LB/amp/ara--> 9 colonies, Glow: yes

-DNA: LB/amp--> 7 colonies, GLow: no

-DNA: LB--> many colonies, Glow: no

HELP ASAP; Please help me understand my lab results, so be detailed to clearly understand

Then , Please include answers to the question below to include in your response

1. what role does ampicilin (amp) and arabinose (ara) play in the experiment.

2) Because GFP was isolated from jelly fisht, what modification to the GFP DNA had to be made to result in expression in E. coli?

BACKGROUND INFORMATION

Transformation of GFP and the pGLO Plasmid GFP is a commonly used reporter protein in research labs, as the fluorescence creates a marker protein that can be used in many types of cell biology and biochemical studies. In basic research, GFP is often fused to a specific target protein of interest, creating a chimeric reporter protein. GFP has been used as a reporter protein to study blood vessel and tumor progression in mice, brain activity in mice, and malaria eradication in mosquitoes for instance (see website mentioned in notes). In the first week you will use a procedure to genetically transform bacteria with the gene that codes for Green Fluorescent Protein. Following the transformation procedure, the bacteria express their newly acquired jellyfish gene and produce the fluorescent protein, which causes them to glow a brilliant green color under ultraviolet light. During the second week you will purify the protein away from all of the other proteins produced by the bacteria using chromatography, and during the third week you will evaluate the success of the purification procedure and estimate the size (molecular weight) of GFP by using sodium dodecylsulfate polyacrylamide gel electrophoresis (SDS-PAGE). Fundamental to the process of genetic transformation of bacteria are plasmids. In addition to one large chromosome, bacteria naturally contain one or more small circular pieces of DNA called plasmids. Plasmid DNA usually contains genes for one or more traits that may be beneficial to bacterial survival. In nature, bacteria can transfer plasmids back and forth allowing them to share these beneficial genes. This natural mechanism allows bacteria to adapt to new environments. The occurrence of bacterial resistance to antibiotics is due in large part to the transmission of plasmids which contain antibiotic resistance genes. The pGLO plasmid contains the gene for GFP, and also contains the gene for the enzyme Î²-lactamase (bla), which provides resistance to the antibiotic ampicillin. The Î²-lactamase protein is produced and secreted by bacteria that contain the plasmid. Î²-Lactamase inactivates the ampicillin present in the LB nutrient agar, allowing bacterial growth. Only transformed bacteria that contain the plasmid and express Î²-lactamase can survive on plates that contain ampicillin. Only a very small percentage of the cells take up the plasmid DNA and are transformed. Untransformed cells cannot grow on the ampicillin selection plates. pGLO also incorporates a special gene regulation system, which can be used to control expression of the fluorescent protein in transformed cells. The gene for GFP can be switched on in transformed cells by adding the sugar arabinose to the cellsâ nutrient medium. Selection for cells that have been transformed with pGLO DNA is accomplished by growth on antibiotic plates. Transformed cells will appear white (wild-type phenotype) on plates not containing arabinose, and fluorescent green when arabinose is included in the nutrient agar medium.

The transformation procedure involves three main steps. These steps are intended to introduce the plasmid DNA into the E. coli cells and provide an environment for the cells to express their newly acquired genes. 1) Cells are first treated with a solution of CaCl2, which is thought to neutralize the repulsive negative charges of the phosphate backbone of DNA and the phospholipids of the cell membrane, allowing the DNA to adhere to the cells. This is referred to making the cells âcompetentâ (i.e. the cells are capable, or competent, to take-in exogenous DNA). 2) Cells are then subjected to a heat shock, which is thought to increase the permeability of the cell membrane, allowing the cells to take-in the plasmid DNA. 3) Cells are allowed to grow in a ârecoveryâ phase in the absence of ampicillin. During this time the cells begin to produce the Î²-lactamase protein, which will allow them to survive when they are subsequently placed on agar plates containing ampicillin.

For the first week section of lab

To eac

h of two microfuge tubes, add 250ul of transformation buffer. Keep these tubes on ice.

Using a sterile loop, pick one colony of bacteria from the LB plate. Transfer this colony to one of the microfuge tubes.

Gently vortex the tube until the colony is dispersed. Repeat for the second tube. Add 0.08ug of DNA to one of these tubes (+DNA tube).

Incubate both tubes on ice for 10 minutes. Incubate both tubes at 42Â°C for 50 seconds.

Incubate both tubes on ice for 2 minutes. Add 250ul of LB broth to each tube and incubate at room temperature for 10 minutes. Flick each tube gently. Add 100ul of t

his transformation mix to the appropriate plates.

Results For plates:

+DNA: Has the E. Coli pGlo plasmid and - DNA plates do no have EColi pGLo plasmid .

Amp means ampiclin and Ara means arabinose on agar plates

+ DNA Plate LB/amp/ara--> white 9 colonies, Glow: yes

+DNA LB/amp--> 7 colonies, GLow: no

--DNA LB/AMP- 1 colony so no colony growth and no glovw

-DNA: LB--> many colonies, Glow: no

Please explain significance of result or thand the reason for the results in scientific terms based on the background information provided and your own knowledge to be detailed. Would these results be expected as wll.

Please I need help answering those questions i always lose bunch of points i'm not doing it correctly.

Use information from Nature Reviews Microbiology to answer the following question.What is the role of EF-G and EF4 in protein synthesis? Under what circumstances does EF4 participate in translation and what is its role?

from this reading The Highly Conserved LepA Is a Ribosomal Elongation Factor that Back-Translocates the Ribosome Qin Y,Polacek N, Vesper O, Staub E, Einfeldt E, Wilson D.N, and Nierhaus N.H. Cell 127: 721-733 (2006).

Q2. In which species is Lep A found and in which ones is it absent? Is the result expected based on your knowledge of the endosimbiosis theory?

Q3.

3a What is the percentage of identity between LepA and its ortholog genes?

3b. (5pts) Indicate what domains are conserved between Ecoli EFG and LepA, and which ones are not.

3c. What do grey and black boxes in the sequence alignment indicate?

Q4. Analysis of in vivo experiments shown in Figure 3. Only analyze graph on the left side of the figure.

4a. What is the difference between the bacteria whose growth are shown by the blue and the green curves? What can be concluded about the effect of EFG on bacterial growth?

4b. Which protein is expressed by bacteria whose growth is shown by the yellow curve? Does the expression of this protein affect bacterial growth? Compare the yellow and blue curves. How can this result be explained?

4c. Explain why the addition of IPTG results in lower bacterial growth. Compare the yellow and red curves?

4d. Why is the green curve an important control of the experiment? The green curve.

The next questions are based on the reading of the article Elongation factor 4 (EF4/LepA) accelerates protein synthesis at increased Mg2+ concentrations.

Elongation factor 4 (EF4/LepA) accelerates protein synthesis at increased Mg2+ concentrations Pech M, Karim Z, Yamamoto H, Kitakawa H, Qin Y, and Nierhaus K. PNAS 108: 3199-3203(2011)

Studies done in E. coli using a knockout mutant of the lepA gene (ÎlepA , lepA gene has been deleted) did not show any phenotype when grown in rich LB medium. This result was unexpected due to the high level of conservation of EF-4 among species.

Q5. Equal amounts of wild type and mutant cells (lacking the lepA gene) were mixed and co-cultured for 24h. The population distribution was determined every 4 hours. Figure 1 indicates changes in the % of mutant cells over several generations.

Q5a. What is the question that researchers addressed in the experiments shown in Figure 1?

Q5b. Which curve represents the control of the experiment? Do the two strains grow at similar rate? How do you know?

Q5c. Do high salt concentration and/or low temperature have any effect on the growth of mutant cells?

Q5d. What can you conclude about the role of LepA on bacteria growth? When is this protein important?

Q6.

6a. (6pts) Where in the cell is EF4 located? Did you expect that this would be the EF4 location? Why or why not?

What is the question that the researchers want to address in the experiment shown in Figure 2?

6c. Analyze the green and red bars graph shown in Figure 2. What technique was used to detect EF4? Is there any change in EF4 localization?

Q7. Summarize the main points of the model shown in Figure 4

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BIOLOGY 1A03 Lecture Notes - Gene Expression, Model Organism, Prokaryote

BIOLOGY 1A03 Full Course Notes

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