BIOLOGY 1A03 Lecture Notes - Lecture 10: Insulin, Proteome, Alternative Splicing

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13 Oct 2015

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BIOLOGY 1A03 Full Course Notes

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Bio 1a03 lecture 10 the human proteome: the human proteome is the full number of proteins in our genome. Our genome only shows between 20,000 to 25,000 protein encoding genes, but over 1,000,000 proteins have been identified. This means that a single gene can encode multiple proteins. This is due to multiple reasons such as alternative splicing and post translational modifications. The composition of our proteome can change in response to internal and external signals: the change in these signals causes the body"s homeostatic mechanisms to become activated. Following a meal, the body"s glucose levels increase, which causes the b cells in the islets of langerhans located in the pancreas to secrete a protein called insulin, which decreases blood glucose levels. Insulin is a small protein which is 110 amino acids in length. However, the insulin protein secreted from the beta cells is made up of 51 amino acids.

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QUESTION 3

What is the purpose of chromatin-remodeling enzymes in human cells?

The enzymes control the rate of translation of an mRNA transcript

The enzymes add phosphate or methyl groups to histone tails

The enzymes slide nucleosomes farther apart or closer to each other

The enzymes send damaged proteins to the proteasome for degradation

The enzymes cause DNA looping to occur

QUESTION 10

If you can drink milk as an adult, it means that you have inherited a mutation in the an enhancer for your lactase gene (the gene that encodes the enzyme you need to break down lactose). Predict the effect of this mutation:

The mutation changes the number of domains in the enzyme, which makes it work more efficiently

The mutation changes the amino acid sequence of the lactase protein

The mutation increases the number of copies of the lactase gene that will be found in your genome

The mutation changes whether the lactase sequence is found in an intron or exon

The mutation affects the expression of the lactase gene

QUESTION 12

What determines where in the genome a transcription regulator will bind?

Transcription regulators bind to the 5' UTR region of a gene

Regulators bind via complementary base-pairing to certain DNA molecules

Covalent bonds form between the transcription regulator and the atoms of the DNA backbone

Every eukaryotic gene has a different transcription regulator that will bind to the 5' end of the gene

Transcription regulators bind to specific DNA sequences via multiple weak non-covalent interactions

QUESTION 15

What is the histone code used for?

		Phosphorylation and acetylation of DNA affect its ability to be compacted
		Changes to the sequence of DNA change whether DNA will wrap around histone proteins
		Covalent modifications of histones affect the ability of the transcription initiation complex to form
		Histones provide the codon sequences needed for translation to occur
		The histone code affects which amino acids will get added to a polypeptide

(BIOCHEMISTRY QUESTION)

A. Gluconeogenesis is not just the reverse of glycolysis. Briefly describe one of the steps catalyzed by different enzymes in glycolysis and gluconeogenesis.

B. Explain how a biochemist might dicover that a certain enzyme is allosterically regulated.

C. What are the regulatory implications for the cell with regard to ATP & AMP, given the relative concentrations of ATP & AMP in a cell?

D. Describe the function of fructose 2,6-bisphosphate in overriding the control of gycolysis and gluconeogenesis in liver cells in response to lowered blood glucose levels.

E. The human disease beriberi is caused by a deficiency of thiamine in the diet. People with severe beriberi have higher than normal levels of pyruvate in their blood & urine. Explain this observation in terms of specific enzymatic reaction(s).

My Responses: Could you tell me if these are correct? If not, could you provide the correct answer and explanation?

A. Its a cellular process in which glucose is produced from pyruvate, amino acids, lactate, and other biogenic precursors.

B. They might learn that an enzyme is allosterically regulated if that protein or enzyme undergoes a conformational change modulated by the binding of one or more modulators/effectors to alternate sites on the protein, resulting in a change in its activity. And they usually have more than one polypeptide chain.

C. The regulatory implications for the cell would be that all activity would increase and concentrations would go up unless bound to PFK-1 and then the overall activity would drop.

D. Low blood glucose is when glucagon signals the liver to produce and release more glucose (gluconeogenesis) and stop consumption. Fructose 2, 6-bisphosphate mediates rapid hormonal regulation of glycolysis and gluconeogenesis.

E. Pyruvate is the product of both carbohydrate and amino acid catabolism that enters cellular respiration in the mitochondria when converted to acetyl-CoA catalyzed by the PDH complex. The first step in the PDH complex reaction is a decarboxylation reaction that cannot be catalyzed without the enzyme thiamine pyrophosphate (TPP). This coenzyme is a derivative of thiamine or vitamin B1.

sapphireswan33

Please help me answer this multiple choice questions: (please answer all questions)

No explantion needed just the answer needed.

physiology and neurobiology questions below.

31. Systemic arterioles dilate in response to _____.

A. Increased CO2 levels in the tissue

B. Decreased O2 levels in the tissue

C. Decreased pH in the tissues

D. All of the above

32. Blood in the pulmonary arteries ______

A. Contains hemoglobin which is about 98.5% saturated with oxygen

B. Has a PO2 of about 40 mmHg

C. Both of the above

D. Neither of the above

33. Completion of first meiotic division of oogenesis yields.

A. One secondary oocyte

B. Four primary oocyte

C. Four mature ova (egg cells)

D. Four secondary oocytes

34. The final absorbable products of chemical digestion occurring in the brush border of the small

intestine include:

A. Monosaccharides and amino acids

B. Proteins and chylomicrons

C. Disaccharides and amino acids

D. Monosaccharides and disaccharides

35. The hemoglobin oxygen curve saturation curve plots ____ on the dependent (Y) axis and ____

on the independent (X) axis.

A. Oxygen concentration; hemoglobin concentration

B. % oxygen saturation of hemoglobin; PO2 of blood

C. % oxygen saturation of hemoglobin; PCO2 of blood

D. Hemoglobin concentration; oxygen concentration

36. In contrast to the female hypothalamic pituitary-sex steroid axis, control of the male axis is

aimed at ____.

A. Allowing spermatogenesis to occur just once a month

B. Keeping levels of pituitary gonadotropins relatively constant in blood

C. Keeping levels of hypothalamic releasing hormones higher than usual in blood

D. Causing a positive feedback effect of sex steroid up on gonadotropins

37. Which of the following will correct acidosis?

A. Speed up the proton pump

B. Buffering of protons with phosphate in the tubular lumen

C. Renal metabolism of glutamine

D. All of the above

38. Epithelium with a brush border (microvilli) is characteristics of the mucosa found in

A. Duodenum

B. Proximal Tubule

C. Both of the above

D. Neither of the above

39. The transport maximum (Tm) for glucose, addition filtered glucose

A. Is no longer filtered

B. Appears in urine

C. Is secreted

D. Is reabsorbed

40. Stroke volume is equal to ____.

A. End-diastolic volume alone

B. End-diastolic volume plus end-systolic volume

C. Cardiac output minus heart rate

D. End-diastolic volume minus end-systolic volume

41. The long term solution to a change in blood pH involves

A. Digestive System

B. Respiratory System

C. Buffers such as hemoglobin

D. Renal System

42. The left heart receives blood from ___ and pumps blood out through the ____.

A. Superior vena cava; pulmonary trunk

B. Pulmonary veins, pulmonary trunk

C. Pulmonary veins; aorta

D. Pulmonary arteries; aorta

43. Selection and activation of specific B lymphocytes may lead to all EXCEPT_____.

A. Formation of memory cells

B. Secretions of antibodies

C. Activation of complements to destroy tagged antigen

D. Secretion of perforin

44. Bile is stored and released into the duodenum from the

A. Liver

B. Pancreas

C. Gall Bladder

D. Duodenum

45. Beta oxidation of fatty acids yields _____,which then can be further oxidized to produces ATP.

A. Glycogen

B. Amino acids

C. Keto acids

D. Acetyl CoA

46. The relationship between the loop of Henle and the vasa recta capillaries function.

A. Absorption of glucose, amino acids and creatinine

B. Countercurrent exchange

C. Countercurrent multiplication

D. All of the above

47. Anterior pituitary production of Follicle Stimulating Hormone (FSH) is decreased by

A. Testosterone from Sertoli cells

B. Inhibin from Sertoli cells

C. Inhibin from interstitial (Leydig) cells

D. Luteinizing Hormone (LH) from granulosa cells

48. A response to acidosis would involve

A. Slowing down the proton pump

B. Greatly increased excretion of HCO3- (bicarbonate ions)

C. Both of the above

D. Neither of the above

49. The conversion of spermatid to spermatozoa occurs

A. By differentiation process in the seminiferous tubule

B. In epididymis

C. By meiosis, in the seminiferous tubule

D. In the prostate gland

50. Antibody-mediated immunity defends against ____.

A. Virus infected cells

B. Viruses and bacteria in the blood or body fluids

C. Bacteria only

D. Viruses only

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BIOLOGY 1A03 Lecture Notes - Lecture 10: Insulin, Proteome, Alternative Splicing

BIOLOGY 1A03 Full Course Notes

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