COMMERCE 4QC3 Lecture Notes - Aph Technological Consulting
1 Jun 2014
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The best solution is x1 = 500, x2 = 400. The value of d3 is underachieved by 100 cabinets. = 100, meaning the two-drawer sales goal. Purchase t = 20 television ads, and n = 20 newspaper ads. The budget constraint is 000 over the constraint (total budget = 000) and the minimum tv spots goal of 10. Solution: see file p7-21. xls, sheets r1, r2, and r3. The final solution (shown in sheet r3) is to purchase 10 tv spots and. The exposure goal will be short by 0. 75 (= 75 000 persons). The optimal solution is x1 = 15,x2 = 20, and d1 satisfied. Since the goals have priority, they can be rewritten in this order, yielding to the absolute completion of each goal before attempting to achieve the next goal. + + p2d2 minimize = p1d1 where p1 = meet class and study goal. = underachievement of class and study goal.
