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Tutorial 3 work.docx

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Tutorial 3 8. qa  max ht. = v^2 / 2g  = 16^2 / (2*9.8)  = 13.06 m  ­­­­­­­­­­­­­­­  qb  time of flight = 2v /g  = 2*16 / 9.8  = 3.265 s  ­­­­­­­­­­­­­­  qc  since the time of 8s is more than the time of flight,  the stone will be back to the ground  ­­­­­­­­­­­­­ ­­­­­­­­­­­­­­ ­­­­­­­­­­­ ­­­­­­­­­­  qd  s = vt ­ 0.5gt^2 taking upward direction as +ve  plugging in,  s = 16*2.4 ­ 0.5*9.8*2.4^2  = 10.176 m above the ground Example:Astone is thrown horizontally at 15 m/s from the top of a cliff that is 44 m high. Answer the following questions assuming no friction. a. How long does it take the stone to reach the ground? b. How far from the base of the cliff does the stone strike the ground? Part a solution: G: The initial vertical velocity = 0 m/s, The vertical distance = 44 m, and the initial horizontal velocity is 15 m/s F: The time to fall to the ground E: d(y) = v(y)*
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