MATH 100 Lecture 3: Solving inequality and equality with polynomials

• School: UBC Okanagan, UBC OK
• Department: Mathematics
• Course: MATH 100
• Professor: Majid Jaberipour

Document Summary

Use =b 2 4ac to solve for delta ( ) If the calculated delta"s value is greater than 0, then it has two roots. If delta equals 0, then it has one root. If delta is less than 0, then it does not have any real root. Solve 2x 2 10x+12 = 0: calculate delta: =(-10) 2 4(2)(12) = 100-96 = 4, put 4 (calculated delta) into x = 2(2: be careful since the square root of a number , therefore, two roots need to be calculated since there is 4, first root: x = First, you need to find the root of the equation which in this case is x=-b/a. Use the sign table to find the solution: Then use the sign table according to its rules: Therefore, the solution is x 2 because if it was 3, then the value of the equation would result in a -3 which is smaller than 0.