AER 416 Lecture Notes - Lecture 21: Angular Momentum, Momentum, Escape Velocity

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Limr =0 d =f. dr= gmm r2 dr. Angular momentumis constant. r2 = angular momentum mass. In equal times, the area swept out by the radius vector of a satellite are equal. Where 2=gm =3. 986 1014 m3 s d dt (m r) mr 2+ m 2 r2 =0 m r mr 2+ m 2 r2 =0 r r 2+ 2 r2 =0 r2 =h. R h2 r3 + 2 r 2 =0 r=f ( ) u= 1 r. H=r2 = u2 gives u= 2 h2 + a. cos( c ) Where a and c are integration constants. r= h2. In this equation, r and are the variables. Looking back at the orbit equation, e=0 the path is circle e<1 the path is ellipse e=1 the path is parabola e>1 the path is hyperbola. A satellite describes an elliptical path around its center of attraction. Velocity required to give circular orbit: v =7. 9 103 m s.

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