ENH 733 Lecture Notes - Lecture 6: Anaerobic Organism, Clostridium, Thermal Death Time

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champagneelephant290

28 Mar 2017

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This part of the growth model assumes the doubling of cell numbers in a specific time starting with one cell (in theory), this would look like: Taking the logarithm of the first 10 generations: In microbiology because of the relatively high numbers of microorganisms present cell counts are generally presented in the exponential format. i. e. , 100 is written as 1 x 102. This format, log10 log2, can also be used (less often). Thus after n generations the cell numbers will equal 2 n n0 where n0 is the initial number of cells from this we can create a formula to calculate the generation time. The generation time (g) is defined as the time taken for the population of cells to double i. e. , the time for one cell to divide into two. We already know that after n generations the cell numbers equal 2nn0. We designate this value as nt the cell number after n generations.

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A student determined ÎHneutzn for the reaction of sodium hydroxide and acetic acid, using the procedure described in this module. The student added 100.0 mL of 0.8500 M NaOH to 100.0 mL of 0.8404 M acetic acid. Prior to and following the mixing of the acid and base solutions, the following temperature-time data were collected. Time Temperature, Â°C Temperature, Â°C Time Temperature, Â°C min NaOH HOAc min mixture 1 17.52 6 23.28 0.5 17.73 7 23.03 1.0 17.54 8 23.10 1.5 17.75 9 23.06 2.0 17.55 10 22.99 2.5 17.77 11 22.93 3.0 17.57 12 22.89 3.5 17.78 13 22.85 4.0 17.58 14 22.78 4.5 17.80 15 22.73 5.0 mixing mixing 16 22.70 17 22.64 18 22.59 Plot the temperature-time data and determine the mean temperature of the unmixed reagents (average the two initial temperatures. Spell check Determine ÎT of the reaction mixture from the graph. Spell check Calculate the heat absorbed by the reaction mixture. You may assume the density of the reaction mixture was 1.02 g mL-1 and the specific heat of the reaction mixture was 3.822 J g-1 K-1. Spell check Calculate the amount of heat absorbed by the calorimeter, thermometer, and stirrer, using 34.8 J K-1 as the calorimeter constant. Spell check Calculate the total heat absorbed. Spell check Find the total heat released by the reaction of 100.0 mL of 0.8500M NaOH and 100.0 mL of 0.8404 M acetic acid. Spell check Identify the limiting reagent. Spell check Find ÎHneutzn for the reaction

BCC Specimen

Material: transformer iron

Calculate grain size by intercept method using the data below

(Me) eye piece magnification: 10

(Mo) objective magnification: 50

Scan # # of grains apparent length of scan

1 3 1cm

2 3 1cm

3 4 1cm

4 4 1cm

5 5 1cm

___________________________________________________________

Total: G= 19 L=5cm(Me)= _____________

Â· Actual grain intercept distance= (L)/(G*(Me)*(Mo)) = ______________________

Â· Grain size(from ASTM standard E112) =_____________________________

Â· Assuming equiaxed grains calculate the number of grains in 1m^3 of this sample (note:P(iron)=7.88 g/(cm^3) â this information may be useful)

ENH 733 Lecture Notes - Lecture 6: Anaerobic Organism, Clostridium, Thermal Death Time

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