PCS 224 Lecture Notes - Lecture 7: Electronvolt, Drift Velocity
27 Nov 2015
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L = 0. 5mm convert to cm = 0. 05 cm. R = l/ (qa) q is sigma. Answer is b) the y axis because v = ir. I = v/r we want current to be bigger so we need a smaller resistance. Current goes from positive terminal to the negative. Q is the charge, v is the drift velocity and b is the magnetic field. F(magnetic force) = i x b = i cross b. Magnetic force is pointing to the left. En = -13. 6 / n^2 = -13. 6 /4 = 3. 4 => 13. 6 3. 6 = 10. 2 ev. Hf = 1240 nm ev / wavelength (nm) => 1240e-9 / 13. 6 = 91. 2 nm. The 2s and 1s are split into 2 parts in a) In b) the 1s and 2s are brought together". The energy bands when a large number of sodium atoms are assembled to form a solid. At 3s we have ef (fermi energy level)
