CHEM 281 Lecture Notes - Lecture 2: Pentene, Butene, Magic 2Ch

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Alkenes are hydrocarbons which have at least one double bond. The homologous series must start with 2 carbons to form a double bond. There are two possible isomers for butene as to where the double can go. Only the position of the functional group does (in this case the double bond). The position of the double bond must be given. If isomers exist it is always given as the carbon number in the chain that it follows. If it is possible to have positional isomers, the position. Ch3 number of the double bond must be given. You must also start to think about looking at these molecules from either end or if we flipped the molecule 180 , would it be the same as the one we have already drawn. 2-pentene ch3 ch = ch ch2 . Same as 2-pentene but flipped 3-pentene does. One of the bonds can break and join to two other atoms.

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