SA 150 Lecture Notes - Lecture 6: Equivalence Point, Titration, Starch

• School: Simon Fraser University
• Department: Sociology and Anthropology
• Course: SA 150
• Professor: Amie Mc Lean

Document Summary

Find an unknown concentration by slowly adding a known concentration until the equivalence point: find concentration of a reducing agent, procedure: 1. Titrate the reducing agent with kmno4 (powerful oxidizing agent) + 8h+ + 5e mn2+ + 4h2o: the reducing agent will change mno4. Mno4 purple colourless: equivalence point is when you see the first hint of purple in the flask. There is no longer any reducing agent left to convert the purple mno4 into colourless mn2: calculation sample. 25. 00 ml of unknown [cu+] is titrated to equivalence point with 18. 73 ml of. + 8h+ +5e mn2+ + 4h2o (from. 5x[cu+ cu2+ + 1e ](we know cu+ is being ox ) + 8h+ + 5cu+ mn2+ + 4h2o + 5 cu2+ M = mol/l moles = m x l = (0. 200 m)(0. 01873 l) = 0. 003746 mol mno4. [cu+] = mol/l = 0. 01873 mol / 0. 02500 l. [cu+] = 0. 749 m cu: calculation example.