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BIOL 2000 Lecture Notes - Peptide, Heterokaryon, Zygosity

Course Code
BIOL 2000
Joseph Rasmussen

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Chapter 6-3
One-gene-one-enzyme hypothesis
Modified to one gene produces one polypeptide since some enzymes are
multiple polypeptides
If one gene can feed other two genes, it must have an accumulation of the
other things needed. (The last mutation- as it has one and two)
Mutant one can not feed anyone else
Mutant two can feed mutant one
Mutant three can feed mutant one and two
Interfering Gene Interactions
Complementation test
o Determine if mutation genes are mutations of one gene or of 3 genes
o Consider where 2 lines ($ and #) are alleles of one gene (w1), the
third line (&) is an allele of a second gene (w2)
o If we make pairwise crosses amongst the three lines ($ x #, $ x &, & x
#) progeny of crosses between alleles of the same gene will show
no complementation, progeny of crosses between alleles of
different genes will show complementation
o In the first cross, the F1 progeny will have no wild type copy of w1
o Second cross, the F1 progeny have one wild type copy of both w1 and
w1 genes
Rules for complementation test
o Can only be done with recessive mutations
o If the mutations are in different genes, the two mutations will
complement one another (progeny will be wild type)
If you have a parts car and a driving car, a mutant in one will
not affect the other
o If the mutations are alleles of the same gene, the two mutations will
not complement one another (progeny will be mutant)
If you have a parts car and a driving car, a mutant in both cars
will affect the other (no parts to switch- both will be affected)
Heterokaryon= variation on a complementation test
Cells have two nuclei in a common cytoplasm
Products of two nuclear genomes act together in the common cytoplasm
o 2 heterozygous (1-arg.2-ARG x 1-ARG.2-arg) crossed can result in a
working phenotype
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