MATH125 Lecture Notes - Lecture 8: Linear Combination, Row Echelon Form, Coefficient Matrix

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MATH125 Full Course Notes
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With (i), isolate t (i") t = 4 - 2u + w - 2x + z. With (ii), isolate v (ii") v = -2 - 2w - 3x - 9z. With (iii), isolate y (iii") y = 3 - 3z. A solution for (i) can be found by checking arbitrary numbers for u, v, w, x, y, z then compute t accourding to (i") Variables t u v w x y z. Free in (ii") x x x x x x. Free in (iii") x x x x x x. + u(-2, 1, 0, 0, 0, 0, 0) \ + w(1, 0, -2, 1, 0, 0, 0) | for specific choices of numbers for u, w, x, z. + x(-2, 0, -3, 0, 1, 0, 0) | this is a linear combination of the 4 vectors. + z(1, 0, -9, 0, 0, -3, 1) / finished. Finding the solutions of these systems of linear equations was "easy"

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