BIOL 1090 Lecture 4: BIO 1090 - Lecture 5 (Sept 25)

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We can see that genes a & b are sitting independently from one another. For two different genes there are 2x2 = 4 possible haploid gamete outcomes. Combining 4 different gametes from both parents 4x4 = 16 diploid genotypes. For n different genes assorting independently (2x2x2) n=2n haploid gametes. Ex: genes within a human chromosome are 23 thus, 2 at the power of 23 equals. The further apart the two genes are, the more likely they will sort independently . Forked line method used to predict the outcome of a cross involving 3. Note: since a heterozygote may have the same phenotype as the homozygous that is dominant, a test cross may be performed to determine the individual"s genotype. In a test cross the person of unknown genotype must be crossed with a. Pedigrees & human genetics: they show the relationship that exists between family members, generally, a phenotype is mapped onto the relationship diagram.

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