CHEM 1040 Lecture Notes - Lecture 9: Bipyramid, Ion, Electron Configuration

• School: University of Guelph
• Department: Chemistry
• Course: CHEM 1040
• Professor: Joe Prokipcak

Document Summary

Chem 1040- lecture 9- review questions: electron configuration. The number of possible electron configurations is equal to the number of electrons in the outer shell: a. 4s23d7 or 3d74ss are acceptable answers: cobalt is paramagnetic, because it has unpaired electrons, there are 4 unpaired electrons in the cobalt cation. The two 4s electrons were removed first, followed by one 3d electron, creating the configuration above: mg2+, o2-, na, f-, na+ The atom in the lowest row of the periodic table will always have the largest atomic radius. Na is the largest atom because it is the only atom in the third row, while the rest are in the second. Mg2+, o2-, f-, na+ are isoelectronic atoms, meaning they have the same electron configuration. To find which of these is the largest, you must find the electron to proton ratio. The atoms with the highest electron to proton ratio (e/p) are the largest: 4s13d10.