CHEM 1040 Lecture Notes - Lecture 2: Sodium Hydroxide, Stoichiometry, Chemical Equation

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A: chemical equations, classification, balancing reactions, molecular reactions vs. net ionic equations, reaction stoichiometry, relationships of reactants/products, limiting reagent, theoretical and percent yields, multiple reactions processes, titrations. Before we start this section, do on your own chapter 3 & 5. Problems: 3. 37, 3. 39, 3. 45, 3. 61, 3. 65, 3. 67, 3. 73, 5. 75, 5. 77, 5. 87, 5. 119, 5. 137, 5. 143. The stoichiometric features in the reaction are: To carry out this reaction on a molecular scale we would need: 1 molecule c2h5oh (7. 65x10-23g, 3 molecules o2 (15. 9x10-23) Therefore the mole quantity (6. 02x1023) puts the very small quantities into more measurable terms. The coefficients in a chemical reaction relate the number of moles of each component in the process. Need to be able to calculate the number of moles in any situations. To practice the manipulation of mole calculations involving different states, here are 2 examples: Calculate the g naoh(s) needed to make 300ml of a 25 mol/l naoh soln.