ENGG 2230 Lecture : Ch 2 Solutions.pdf

• School: University of Guelph
• Department: Engineering
• Course: ENGG 2230
• Professor: Bahram Gharabaghi

Document Summary

2. 1 for the two-dimensional stress field in fig. 3000 psf (cid:86) (cid:32) xy (cid:86) (cid:32) yy. Find the shear and normal stresses on plane. Solution: make cut aa so that it just hits the bottom right corner of the element. Now sum forces normal and tangential to side aa. 0 (cid:32) (3000sin30 500cos30)lsin30 (cid:16) (2000cos30 500sin30)l cos30 (cid:16) L (3000cos30 500sin30)lsin30 (500cos30 2000sin30)l cos30 (cid:16) (a) (cid:16) (cid:16) P2. 1, change the known data to (cid:86)xx (cid:32) 2000 psf, (cid:86)yy (cid:32) 3000 psf, and (cid:86)n(aa) (cid:32) 2500 psf. Compute (cid:86)xy and the shear stress on plane aa. Solution: sum forces normal to and tangential to aa in the element freebody above, with (cid:86)n(aa) known and (cid:86)xy unknown: (cid:166) 2500l ( cos30 (cid:86) (cid:16) xy sin30 (cid:113) (cid:14) (cid:16) (cid:86) xy (cid:113) (cid:14) Solve for (cid:86) (cid:32) xy (2500 500 2250)/0. 866 (cid:16) (cid:16) (cid:124) (cid:16) In like manner, solve for the shear stress on plane aa, using our result for (cid:86)xy: (cid:166)