ENGG 3430 Lecture Notes - Lecture 12: Thermal Conductivity

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Steady-state heat conduction inside the cylinder with constant k and without heat generation: Temperature distribution inside the cylinder: express temperature (t) as a function of radial distance (r). C1 and c2 are two constants of integration and can be evaluated by using boundary conditions: By solving these equations for c1 and c2 one obtains: Heat transfer inside the cylinder: once temperature distribution is available, heat transfer at any location can be calculated by using fourier law of conduction; i. e. , Steady-state heat conduction inside the sphere with constant k and without heat generation: A c dr ka c dt dr q gen. Temperature distribution inside the sphere: express temperature (t) as a function of radial distance (r). Integrate the differential equation twice at r=r1, t=t1: Ak dt dr dt dr at r=r2, t=t2: Inner radius radius ty) conductivi (inner radius) (outer radius) Conduction thermal resistances: steady-state heat transfer (i. e. , constant thermal conductivity (i. e. , k = constant, no internal heat generation (i. e. ,

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