PHIL 2100 Lecture : PHIL MONDAY MARCH 5th.docx

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limeoyster176

28 Mar 2012

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Scope and adequacy chapter eight in both cases the premise in question provides no reason to believe the conclusion. Adequacy does not work the same way as the other two the prem may be true, supply reasons to believe the conclusion, and still be inadequate. When we take all these three criteria together , we have the tools to assess whether or not an arg is sound; that is whether the prems are true and the prems support the conclusion. Scope intent of the author of an arg and the context makes a huge difference is part of that intent. When we refer to the scope of an arg, we are referring to how wide-reaching its implications are or are meant to be, or how strong of a conclusion is meant to be drawn. An arg about black f150s driven by middle aged suburban men in the. Implications can only fit into the description made by the arg.

Related Questions

2) a) A tube consists of two pipes, one just slightly smaller thanthe other, that can slide in and out like a telescope. Each pieceis approximately 35cm long. A tuning fork is held at one end as onetube is slid into the other. The apparatus is heard to resonate atvarious total lengths, which are recorded in the table below.Discuss which harmonics these are and whether the pipe likely to besealed at the opposite end. Sketch these harmonics. Also determinethe frequency of the tuning fork. [Note: The studentâs measurementsare close, but might not be precise.] Make sure you state theevidence for your conclusions.
Lengths (cm)
46.2
57.9
69.5
b) A variety of strings are seen to vibrate as seen below. Someends are fixed in place and some are free to slide along a rigidrod. The lengths, masses and tensions are given. Rank theseaccording to the frequency of the oscillation. (Least togreatest)
L=40cm, m=10g, FT=100N L=30cm, m=20g, FT=150N
L=40cm, m=20g, FT=150N L=30cm, m=20g, FT=100N

I had previously worked this problem but after trying toformulate the Lagrange for r and phi, my work became a jumbled messthat took several lines of paper to write down. I thought this wasa problem so I checked Cramster to make sure I was following thecorrect path and found that the Cramster formula for Kinetic Energywas much different from mine. I found the correct answer forPotential Energy, but I do not understand how the Kinetic answerwas formed. The way I originally started the problem was by makinga drawing which was exactly like the one in the answer key andwriting out the conversions from Cartesian to sphericalcoordinates.

x = rsin(Î±)cos(Ï)

y = rsin(Î±)sin(Ï)

z = rcos(Î±)

The kinetic energy is then

T = (1/2)m[d/dt((rsin(Î±)cos(Ï))^2 + (rsin(Î±)sin(Ï))^2 +(rcos(Î±))^2)]

Applying the time derivative makes a mess of things and trigidentities are not simplifying things which has led me to theconclusion that something must be wrong in my initial setup. What Ido not understand is how the Cramster answer has a kinetic energyof

T = (1/2)m[rdot^2 + (rsinÎ±Ïdot)^2]

If an explanation of how this is achieved can be provided, Iwould be incredibly grateful.

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