ADM 2303 Lecture Notes - Lecture 2: Standard Deviation

• School: University of Ottawa
• Department: Administration
• Course: ADM 2303
• Professor: Phansalker

Document Summary

90th percentile= mean + 1. 645*69. 6 inches= 114. 492 inches: probability= (cid:3040)(cid:3041) (cid:3046) (cid:3032)(cid:3034) (cid:3047) (cid:3040)(cid:3032)(cid:3041) (cid:3042)(cid:3033) (cid:3047) (cid:3032) (cid:3034)(cid:3045)(cid:3042)(cid:3048)(cid:3043) The mean of g= 10* mean of x. The standard deviation g= 10 * standard deviation x: the probability of guessing and getting the question right is. = pick one answer out of the four. The probability of getting all right = ( ) ^10= 9. 536743164*10^-7. Expectation of x squared= 12*0. 1) + (1. 52*0. 2) + (22*0. 4) + (42*0. 2) + ( 102 * 0. 1)= 15. 35. He variance = expected mean of profit squared- mean of profit squared. Standard deviation= square root of variance= 2. 5199 (4dp) = (2. 5199/3) *100% = 83. 9967% profit probability davids profit. He variance = expected mean of profit squared- mean of profit squared: the coefficient variation of retrained profits. Out of the 5, the mean is 84% The mean = 84% of 6(total throws) = 0. 84 * 6 = 5. 04.