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Class Notes for Computer Science at University of Ottawa (UOTTAWA)


UOTTAWACSI 3105Sylvia BoydFall

CSI 3105 Lecture Notes - 5,6,7,8, For Loop, Array Data Structure

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| | ____ boyd(2) boyd(5) boyd(6) boyd(3) boyd(6) boyd(7) | | ___ | | boyd(0) boyd(3) boyd(4) boyd(1) boyd(4) boyd(5) boyd(1) boyd(4) boyd(5) | | |_ _ |
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UOTTAWACSI 2101Najib ZaguiaWinter

CSI 2101 Lecture Notes - Lecture 3: Contraposition, Universal Instantiation, Modus Ponens

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Assignment 1 solutions: t he truth value of fred and j ohn are happy is min(0. 8, 0. 4) = 0. 4. T he truth value of neither fred nor. T hen the given s
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UOTTAWACSI 2110Lucia MouraFall

CSI2110 Lecture 4: Big-O Cheat Sheet

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UOTTAWACSI 2110Lucia MouraFall

CSI2110 Lecture 2: 02-Intuition for Asymptotic Notation

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UOTTAWACSI 2110Lucia MouraFall

CSI 2110 Lecture Notes - Lecture 9: A Priori And A Posteriori, Prnp, Lection

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UOTTAWACSI 2110Lucia MouraFall

CSI 2110 Lecture Notes - Lecture 1: Pseudocode

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An algorithm is a step-by-step procedure for solving a problem in a finite amount of time. We focus on the worst case running time because this is easi
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UOTTAWACSI 2110Lucia MouraFall

CSI2110 Lecture 1: 01-analysis of algorithms

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UOTTAWACSI 2110Lucia MouraFall

CSI 2110 Lecture Notes - Lecture 5: Priority Queue, Total Order, Insertion Sort

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A set of elements each with a given priority. Elements are sorted based on priority not position. In a priority queue, each entry is a pair of (key, el
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UOTTAWACSI 2120Pirooz MirfakhraeiSummer

MCG3131 - Chapter 5-6 Lecture Notes

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UOTTAWACSI 2110Lucia MouraFall

CSI 2110 Lecture Notes - Lecture 6: Binary Tree

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A graph g=(v,e) consists of a set v of vertices and a set e of edges with e={(u,v): u,v in v, u!=v} A tree is a connected graph with no cycles. Interna
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UOTTAWACSI 2110Lucia MouraFall

CSI2110 Lecture 8: Maps, Binary Search Trees

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Stores and retrieves values based on a uniquely identifying search key. Insert takes o(1) but first we need to search for a key duplicate which takes o
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UOTTAWACSI 2110Lucia MouraFall

CSI 2110 Lecture Notes - Lecture 2: History Of The Web Browser, Big O Notation, Text Editor

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We must find a constant c and a constant n0 such that: 1<=n2 for all n>=1 f(n)<=60n2 + 5n2+n2 for all n>=1 f(n)<=66n2 for all n>=1 c=66, n0 =1 ---> f(n
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