MAT 1300 Lecture Notes - Lecture 2: Asymptote, Coefficient, Graphing Calculator
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People model demand and supply by linear functions. Demand= d(p)= -0. 7p+ 8. 7 (slope is negative (-0. 7) as demand reduces when price increases) The equilibrium price is the price when d(p)= s(p) in our case. F(x)=2x2+10x+12: find f(0) ((cid:1688)y intercept(cid:1689))(vertical intercept , solve f(x)=0 (the solutions are called x intercepts or horizontal intercepts. The degree of f is 4 (highest exponent of x) The leading coefficient of x is -1 ( the coefficient of x with the highest exponent ) P(x)= anxn + an-1xn-1 + . + . + a1x + a0. Take test values: 2 , f(2) >0, 0 , f(0)<0. 3 ,f(-3)>0 answer x>1 or x< -2 (1,+infinity)u(- infinity , -2) We know (x-2)(x2+2x+1)=0 (x-2)(x+1)2 = 0 when x=-1 or 2. Take test values: 3 , f(2) >0, 0 , f(0)<0. 2,f(-3)<0 answer x< -1 or -1