MATA23H3 Lecture Notes - Lecture 10: Solution Set, Elementary Matrix, Selenium

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Mata23 - lecture 10 - invertiblity, homogeneousness, and subspaces. Invertible matrices continued: example 6: assume that matrices a, b and a + b are invertible. A(a + b) 1b. (note (a 1 + b 1) 1 (cid:54)= (a 1) 1 + (b 1) 1) [(a 1 + b 1) 1] 1 = [a(a + b) 1b 1] 1. Prove a 1 + b 1 = b 1 + a 1. Since a, b invertible, aa 1 = i, bb 1 = i. A, b, a + b are invertible. (a 1 + b 1) 1 = [b 1(a + b)a 1] 1. (a 1 + b 1) 1 = (a 1) 1(a + b) 1(b 1) 1. = a(a + b) 1b: theorem: let a be a n n matrix. A invertible a 1 (cid:126)b rn if a(cid:126)x = (cid:126)b. X1 (cid:126)a1 + + xn (cid:126)an.

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