<p><br />(a) When the nanoparticle's energy is in the range 5(4e-21) J to 6(4e-21) J, what is the approximate temperature? (In order to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.)<br /> K<br />(b) When the nanoparticle's energy is in the range 8(4e-21) J to 9(4e-21) J, what is the approximate temperature? (In order to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.)<br /> ? K<br />(c) When the nanoparticle's energy is in the range 5(4e-21) J to 9(4e-21) J, what is the approximate heat capacity per atom?<br /> ?J/K<br />Note that between parts (a) and (b) the average energy increased from "5.5 quanta" to "8.5 quanta". As a check, compare your result with the high temperature limit of 3k, where k = 1.4e-23 J/K.</p>