AST221H1 Lecture Notes - Lecture 7: Geosynchronous Orbit, Geostationary Orbit, Tidal Force
21 Sep 2019
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Tidal deformation of the surface of the earth. Defining the gravitational acceleration due to the extra mass amounted at the tidal bulge g = Equating this acceleration to the one calculated for any object, (a=g") ensity of the earth, assumed constant g = re 2. For the moon-earth system, h ~ 60cm, which is way less than the 10m of ocean tides. So, ocean tides >bdeformation tides, which is why we can get energy out of ocean tides. An orbit in which the object always comes back to the same spot above the earth at the same time. Has to be a very specific distance above the earth in order to have the same period as the earth"s rotation. The body orbits the same point of the earth at all times. Works mostly along the equator, because it has to orbit the center of mass of the earth. E orbit = 2 it that much energy gravitational =
