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Lecture

Reaction Mechanism With Fast Initial Step (Medium)


Department
Chemistry
Course Code
CHM135H1
Professor
all

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Q2. Reaction mechanism with Fast initial Step (Medium)
You are provided with an overall equation along with its
mechanistic steps. Prove that the rate of slow step is equal
to the rate of the overall reaction
Overall Equation:
2N2O5 ==> 4NO2 + O2 (From Experiment, Rate = K [A])
Mechanism:
2N2O5 <==> 2NO2 + 2NO3 (Fast Step)
NO2 +NO3 ==> NO + NO2 + O2 (Slow Step)
NO3 + NO ==> 2NO2 (Fast Step)
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