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Department
Chemistry
Course Code
CHM135H1
Professor
Kris Quinlan

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LECTURE 12 – Thermodynamics
Slide No. Notes
3-q represents heat, or the transfer of thermal energy, which is another
type of kinetic energy
-restating delta E = -PdeltaV plus q, which q being equal to delta E
plus P delta V
-common kinds of reactions
7- the addition sign is circled because the negative sign for work has already
been included
8-Ex. A)
-A change in volume from 0.274 L to 448L
-W = -p times delta V = -(1atm)(448L-0.274L) = -447.7 Latm times
(101J/Latm)(kJ/1000J) = -45.2kJ
-Negative sign means energy lost, leaving system, so work is done on
surroundings
-Ex. B)
-W = -p times delta V = -1atm(5.6L)(101J/Latm) = -566J
-Ex. B) part 2
-Delta E = q + w = -(484kJ) + (-566J) = -484.6kJ
9 -What is absolutely true is B
-What could be true is all of them, so E
10 -heat capacity depends on amount of substance
-specific heat capacity – the amount is specified
-for water, specific heat capacity is around 2 – so it takes 2J to raise 1g
of water by 1 degree C
-metals have low heat capacities
11 -Ans: A
-Al transfers more energy, therefore melts more wax
12 -calorimeter is the surroundings; reaction is the system
-energy is conserved, so energy that is lost to the system goes to the
surroundings
NEXT
LEC
1-bomb calorimeter – how much water warms up or cools down
-in an insulated box so that any heat lost goes into the water
2-any energy goes into water
-EX. q of surr = q of water = C of water times mass times change in
temperature = 4.18J/gC (250g)(7.48C)(kJ/1000J) = 7.82 kJ
-Q of rxn = - q of surr = -7.82kJ
5- extensive – because enthalpy differs for 1 mole of reactants compared to 5
moles
6- enthalpy is a state function
8-EX.
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Description
LECTURE 12 Thermodynamics Slide No. Notes 3 - q represents heat, or the transfer of thermal energy, which is another type of kinetic energy - restating delta E = -PdeltaV plus q, which q being equal to delta E plus P delta V - common kinds of reactions 7 - the addition sign is circled because the negative sign for work has already been included 8 - Ex. A) - A change in volume from 0.274 L to 448L - W = -p times delta V = -(1atm)(448L-0.274L) = -447.7 Latm times (101JLatm)(kJ1000J) = -45.2kJ - Negative sign means energy lost, leaving system, so work is done on surroundings - Ex. B) - W = -p times delta V = -1atm(5.6L)(101JLatm) = -566J - Ex. B) part 2 - Delta E = q + w = -(484kJ) + (-566J) = -484.6kJ 9 - What is absolutely true is B - What could be true is all of them, so E 10 - heat capacity depends on amount of substance
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