CHM135H1 Lecture Notes - Lecture 3: Molar Mass, Reagent
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CHM135H1 Full Course Notes
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Mass % = (mass element per mol compound/mass of 1 mol compound) x 100% 2 molo(16. 0 g mol)+1mil x x 100% x; molar mass of m. X = 47. 90 g/mol look up mass on periodic table element m is ti compound = tio2. Cac2 + 2h2o hcch + ca(oh)2 need to balance out the elements on both sides. 100. 0g xs ? g - we have more than enough water for reaction to occur. We cannot work in grams, so we have to convert to mols. N2 + 3h2 2nh3 when they react, you have some nitrogen leftover (when you react 2 nitrogen with 6 hydrogen) How much al is needed to react with all of the cr2o3. 0. 281 mol cr2o3 (2 mol al / 1 mol cr2o3) = 0. 562 mol al needed . As you see, you need more al to use all of cr2o3 . = 19 g cr (you clearly have enough cr to use all al)
