HMB265H1 Lecture Notes - Lecture 2: Dihybrid Cross, Mendelian Inheritance, Pea

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28 Nov 2016
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HMB265H1 Full Course Notes
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HMB265H1 Full Course Notes
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Two hypothesis to inheritance: one parent contributes more to an off springs inherited traits. Wrong because it was independent of the parent (reciprocal crosses: blended inheritance- traits of parents contributes to phenotype of child. Dominant: yellow, round, pea pod round, purple, long, green pod, axial. Monohybrid cross pp x pp = f1 all dominant heterozygous selfed -> f2: 3:1 ratio -> law of segregation: two members of a gene pair segregate from each other into gametes and unite randomly (probability). Hybrids crossing: pp x pp= 1:2:1 genotype ratio= 3:1 phenotype ratio. Test cross: reveals unknown genotypes-> unknown genotype x homozygous phenotype. Dihybrid crosses: reveals law of independent assortment (2 copies of each trait in germ cell) Law of independent assortment: from above chance to get pq or pq or qp or qp = 22. Pp qq x pp qq -> p, q + p, q -> pq x pq -> f1: ppqq and ppqq-> 9:3:3:1.

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