PHC320H1 Lecture Notes - Lecture 17: Miscibility, Glycerol, Chemical Potential

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Saturated solution of phenol in water, because that isn"t how much phenol in system, can"t add more phenol into this water based phase. If water rich phase, then you should by definition phenol in water, if phenol rich phase, need to identify the phase. Upper critical temperature isn"t only possibility, a lower critical temperature is possible, where two liquids become infinitely miscible if below some critical temperature or system that displays both upper or lower critical temperature, ex: nicotine in water. Problem: in one phase the concentration of phenol is 7% and phenol rich phase it is 70% po/ (po+wo) (weight of phenol and weight of water) =0. 21. We know total weight is 135 g : po +wo=135 g. So we know total weight of phenol in system is po=0. 21* 135 =28 . 35 g. Then denote weight of first phase as x and weight of second phase as y. P2+w1=y (masses of phenol and water in phase 2)

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