Biology 3466B Lecture Notes - Lecture 5: Zygosity
14 Oct 2017
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If the size and distance travelled differs, you can detect heterozygosity. Ps and pf: frequency of slow allele and frequency of fast allele. Number of f/(number of s + f). e. g. pf = 1/13. You square root a frequency only if the frequency of female and male are the same and if the population fits in the model. In this example, square root is banned because the sample doesn"t fit in the hardy-weinberg model. The alleles are homozygous because there"s only one band. If there are more than one band, it is heterozygote. Multiply one band x 2 and add the number of 2 bands. The bands are not in hardy-weinberg equilibrium because it is missing heterozygotes. The second example is also not in an equilibrium because it doesn"t have a small fraction of other homozygous. From the model, you would expect the same amount of slow homozygous and heterozygous. But, in the example, the numbers are not the same.
