BIOL 2010 Lecture : Notes from all year so far

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pearkoala652

23 Mar 2011

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Gas production of yeast in the presence of glucose and succinate. In this experiment, yeast will be exposed to either a glucose or succinate solution to view their effects on gas production. Time (min) glucose (ml) succinate (ml) control (ml) As expected, the control sample produced no gas. When looking at the glucose sample, the yeast was able to produce co2 quickly and abundantly. This is due to glucose being a part of the initial aerobic reaction that the yeast has. Since the experiments started in an oxygen-available environment, the aerobic reaction would begin, and therefore, the glucose is expected to be used readily. The succinate sample was only able to make a small amount of gas in the two hours. As succinate is not part of this initial reaction, it would not be used quickly. Succinate, however, is part of an anaerobic reaction that the yeast undergoes.

Related Questions

In E.coli the lac operon is controlled by the presence or absence of both lactose and glucose. The lac repressor only allows expression in the presence of lactose, and it is also only activated when glucose levels are low, such that the lac operon is on when lactose is present but glucose is not.

You have cells that are mutant in the gene coding for the Lac repressor (I-). These cells lack the Lac repressor under all conditions. For these mutant cells, state whether the Lac operon will be switched on or off in the following situations, whether the lac repressor (I) is bound to the operator, and whether CAP-cAMP is bound upstream of the promoter.

a. in the presence of glucose and lactose

b. in the presence of glucose and the absence of lactose

c. in the absence of glucose and the absence of lactose

d. in the absence of glucose and the presence of lactose

Given the following mutants and conditions, predict the expression level of the of the lac Z gene. Please indicate your answer with one of followings: no expression, basal level of expression, or activated level of expression. Explain why, in the context of activities by activator and repressor:

I. A mutant of E.coli that has a mutation in the repressor gene (Lac I) for regulating lac operon

a. In the presence of glucose, presence of lactose

b. In the presence of glucose, absence of lactose-

c. In the absence of glucose, absence of lactose-

d. In absence of glucose, presence of lactose-

II. A mutant of E.coli that has a mutation in the cAMP binding site of CAP

a. In the presence of glucose, presence of lactose â

b. In the presence of glucose, absence of lactose â

c. In the absence of glucose, absence of lactose â

d. In absence of glucose, presence of lactose -

amaranthsquirrel358

1.In the bacterial lac repressor, which of these occurs:

		A.In the presence of glucose and the absence of lactose, the repressor is actively produced.
		B.The lac operon can be hyper-induced in the presence of low glucose by the 'cAMP binding protein' (CAMP).
		C.In the presence of lactose and the absence of glucose the lac operon is repressed.
		D.Allolactose is a byproduct of Î²-galactosidase, indicating high lactose when it builds up.

2 In eukaryotes the enhancer elements can be quite a distance upstream or downstream from the promoter, and transcriptional regulation is helped by protein:protein interactions.

True

False

amaranthraccoon830

BIOL 2010 Lecture : Notes from all year so far

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