ITEC 1000 Lecture : Itec1000 Assign3Solutions
10 Jan 2013
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64 different instructions require 6 bits for op code in 19-bit instruction word. The two further bits are used to indicate the addressing mode. There will be 11 (19-(6+2)) bits left for the address field in the instruction format. Using 11 bits as address field of the instruction, this cpu can address 2048 (211 = 2048) different memory locations (ranging from 0 to 2047) using direct and absolute addressing mode. (c) A 14-bit general purpose register can hold 214 = 16384 different values ranging in decimal from 0 to 16383. Using this register as the base in the base/offset addressing mode, the cpu can address 16383 + 2048 = 18421 different memory locations. The value in the accumulator without the overflow bit counted is 001011002 = 4410. All registers are restored from the stack area and execution resumed. a. There are 20 (sectors) x 1600 (cylinders) x 16 (surfaces) = 512,000 blocks on this disk.
