CHM 116 Lecture 22: Addition Aspects of Equilibrium Continued 5
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Ksp = 4. 3 x 10-9 srf2 (s) sr+2 (aq) + 2f- (aq) Now what if we"re given 10. 0 g of srf2 and put it into 1 l of solution. Change grams into moles: (10 g srf2 * 1 mol srf2) / 126 g = 0. 08 moles srf2. Not all of srf2 dissolves because only 1 x 10-3 of solution was added, so the rest goes to the bottom of the test tube. To get rid of strontium, just add fluoride. Use sodium fluoride to dissolve fluoride into it. We can say the 2x is about 0 because of an assumption, but if going back it is incorrect, then we would have to go back and do the quadratic. The adjusted equation after making 2x = 0 would be: 4. 3 x 10-9 = 0. 01x x = 4. 3 x 10-7. Since 4. 3 x 10-7 is nowhere near.
