MAT 095 Lecture Notes - Lecture 27: Quadratic Equation

29 views4 pages
20 Dec 2016
Department
Course
Professor

Document Summary

Provide a generalization to each of the terms listed in this section. Factoring: add, or subtract, all of the terms to make sure one side of the equation is 0, factor all of the polynomial expressions, set each factor equal to 0, solve the resulting equations. Multiplicities: if two of the given factors are the exact same, then the solution would be considered one of the following ways: Quadratic equation: this is the formula for the quadratic equation: ax2 + bx + c = 0. 6y + 3 = 4y2 (6y + 3) (6y + 3) = 4y2 (6y + 3) 4y2 6y 3 = 0 y = ( 6) q( 6)2. 4 4 ( 3) y = y = y = Zero-factor property: if ab = 0, then either of the following: 7m + 4 = 0 (7m + 4) (5m 2) = 0. Squaring property of equality and square root property: squaring property of equality.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related textbook solutions

Related Documents

Related Questions