CHE 1302 Lecture Notes - Lecture 4: Rate Equation, Reaction Rate Constant

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20 Dec 2017
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The first order rate constant k for a particular reaction is 6. 8 10 4 s 1. Use the first order integrated rate law: ln[a]t = kt + ln[a]0. [a]0 = 1. 35 m t = 1420 s ln[a] = (6. 8 10 4 s 1) (1420 s) + ln[1. 35] This separate experiment will have a new set of initial conditions, but the rate law will still be the same and the value of k will still be the same: [a] 0 ln(0. 498) = (5. 868 10 4 s 1) (1000 s) + ln[a]0. = ln(0. 498) + [(5. 868 10 4 s 1) (1000 s)] A particular first order reaction has a half-life of 150 s. if the initial reactant concentration is. For this kind of question, first use the half-life to calculate k: k = 0. 693/t = 0. 693/(150s) = 4. 62 10 3 s 1.

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