MATH 1A Lecture Notes - Lecture 14: Quotient Rule, Power Rule, Product Rule

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26 Mar 2015
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Math 1a lecture 14 3. 2 product & quotient rules, and 3. 3 derivatives of. Let f (x) and g(x) be differentiable everywhere. [f (x)g (x)]= d dx f (x ) g (x)+f (x) d dx g(x) [f g]=f " g+f g" Or, by product rule and power rule: x x ( n)(m xm 1) ( m)+ d dx. 3 ) d dx [ 3 x e x]= d. Proof of product rule lim h 0 f (x +h)g( x+h) f (x)g (x) h f (x)g(x)= d dx. +f (x)g(x+h) f (x) to the numerator. lim h 0 f (x +h)g( x+h) f (x)g (x+h) f (x)g (x)+f (x)g (x+h) h lim h 0. [f (x +h) f (x)] g(x +h)+f (x)[ g(x +h) g( x)] lim h 0. [f (x +h) f (x)] h: g(x+h)+f (x) [g (x+h) g(x)] h h. Notice that as h 0, [f (x+h) f (x )] h.

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