MATH 107 Lecture 1: Polar Form of Complex Numbers

• School: Binghamton University
• Department: Mathematical Science
• Course: MATH 107
• Professor: Sarah

Document Summary

2 ) b ) z z = r r [ c o s ( + ) + i s i n ( + ) ] Dividing two complex numbers: put both complex numbers into their polar forms (1) z sin . 2 ) b) z / z = r / r [cos ( ) + i sin ( )] 2 2 r = 2 + 2 = 2 2. = tan 1 (2/2) = 45 degrees, or /4. Since we have to find the first 3 cube roots, we have to find w , w , and w . Since this is cube roots, n = 3 1/3 w. 0 = 2 2 [cos (( + 2 *0)/3) + i sin ( + 2 *0)/3)] which should equal. = 2 [ c o s ( ( / 1 2 ) + i s i n ( / 1 2 ) ]