f(t)=2+cos(pi/2 t) + sin(3pi/5 t) +cos(pi/8t)
signal is periodic. So, (1/2, 3/5, 1/8) is this correct?
GCF(1,3,1) = 1
LCM(2,5,8)=40
So, 1/40. How would I find f2, f3, f4?
I got f1=(1/40)(20pi)=pi/2
f2=(1/40)(24pi)=3pi/5
f3=(1/40)*(5pi)=pi/8
Question is, when determining GCF(1,3,1) should it be (pi, 3pi,pi)instead? which would = pi instead of 1. So to find f1,f2,f3 Iwould* by pi/40 instead.
PHYS 220A Lecture 5: 005 Understanding Free Body Diagrams
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18 Sep 2016
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