CHM 1046 Lecture Notes - Lecture 14: Sodium Formate, Conjugate Acid, Acid Dissociation Constant

68 views1 pages
School
Department
Course
Professor

Document Summary

Calculate the ph of a solution that is . 250 m in sodium formate (nahcoo) and . 100 m in formic acid (hcooh) Strong/weak acid or base (nahcoo ionic salt hcooh weak acid) Nahcooo really exists as ions ( go to back of problems from 18. 1-. 3 for work out) Has a ph between base only and acid only versions. Contains a weak acid- base conjugate pair. The type of solution is a buffered solution (aka buffer) Ph is based on the acid conjugate base ratio. The amount of acid or base the buffer can neutralize without a significant ph change. Buffer no longer effective when outside the range (0. 1

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related Documents

Related Questions